BizTalk Map Group Kişisine göre Anahtar

Question

Varolan haritanızda, kaynak şemadan bir kişiyi, hedef şemadaki bir kişi ile, türüne ve diğer bir çok mantıka bağlı olarak, haritanın içindeki functoids kullanarak dönüştürür. Hedef şemadan yakın zamanda yapılan bir değişiklikle, verileri gruplayabilmemiz için bir anahtar (kılavuz) düğümü kullanmak için dönüşümü değiştirmem gerekiyor.

// Kişi */[Anahtar = aynı] gibi bir şey için satır içi XSLT komut dosyası uygulamak istiyorum ancak bunun için XSLT'den emin değilim.

Örnek giriş: şu anda

<Person> 
    <PersonType>PartnerParentsFarther</PersonType> 
    <Name> 
     <title>MR</title> 
     <Gender>MALE</Gender> 
     ... 
    </Name> 
    <Address/> 
    <PersonKey> 
     <Key>a1093c4a-7c53-4de5-ad30-cb4140aec58</Key> 
     <ParentKey/> 
    </PersonKey> 
</Person> 
<Person> 
    <PersonType>PartnerParentsMother</PersonType> 
    <Name> 
     <title>MRS</title> 
     <Gender>FEMALE</Gender> 
     ... 
    </Name> 
    <Address/> 
    <PersonKey> 
     <Key>a1093c4a-7c53-4de5-ad30-cb4140aec58</Key> 
     <ParentKey/> 
    </PersonKey> 
</Person> 
<Person> 
    <PersonType>PartnerParentsFarther</PersonType> 
    <Name> 
     <title>MR</title> 
     <Gender>MALE</Gender> 
     ... 
    </Name> 
    <Address/> 
    <PersonKey> 
     <Key>a1093c4a-7c53-4de5-ad30-cb4140aec59</Key> 
     <ParentKey/> 
    </PersonKey> 
</Person> 
<Person> 
    <PersonType>PartnerParentsMother</PersonType> 
    <Name> 
     <title>MRS</title> 
     <Gender>FEMALE</Gender> 
     ... 
    </Name> 
    <Address/> 
    <PersonKey> 
     <Key>a1093c4a-7c53-4de5-ad30-cb4140aec59</Key> 
     <ParentKey/> 
    </PersonKey> 
</Person> 

Örnek çıktı:

<PartnerParents> 
    <Father> 
     <Title>MR</Title> 
     <Gender>MALE</Gender> 
    </Father> 
    <Father> 
     <Title>MR</Title> 
     <Gender>MALE</Gender> 
    </Father> 
    <Mother> 
     <Title>MRS</Title> 
     <Gender>FEMALE</Gender> 
    </Mother> 
    <Mother> 
     <Title>MRS</Title> 
     <Gender>FEMALE</Gender> 
    </Mother> 
</PartnerParents> 

Örnek gerekli çıkış, aynı anahtar değerlerine göre

<PartnerParents> 
    <Father> 
     <Title>MR</Title> 
     <Gender>MALE</Gender> 
    </Father> 
    <Mother> 
     <Title>MRS</Title> 
     <Gender>FEMALE</Gender> 
    </Mother> 
</PartnerParents> 
<PartnerParents> 
    <Father> 
     <Title>MR</Title> 
     <Gender>MALE</Gender> 
    </Father> 
     <Mother> 
     <Title>MRS</Title> 
     <Gender>FEMALE</Gender> 
    </Mother> 
</PartnerParents> 

Answer 1

zaman bu XSLT 1.0 çözeltisi:

<xsl:key name="groups" match="Test/Person/PersonKey/Key/text()" use="."/> 

    <xsl:template match="/"> 
    <xsl:apply-templates select="/Test" /> 
    </xsl:template> 

<xsl:template match="/Test"> 
<Test> 
    <xsl:for-each select="Person/PersonKey/Key/text()[generate-id()=generate-id(key('groups',.))]"> 
    <PartnerParents> 
     <Father> 
     <xsl:for-each select="key('groups',.)"> 
      <xsl:if test="../../../Name/Gender/text() = 'MALE'"> 
      <Title> 
       <xsl:value-of select="../../../Name/title/text()" /> 
      </Title> 
      <Gender> 
       <xsl:value-of select="../../../Name/Gender/text()" /> 
      </Gender> 
      </xsl:if> 
     </xsl:for-each> 
     </Father> 
     <Mother> 
     <xsl:for-each select="key('groups',.)"> 
      <xsl:if test="../../../Name/Gender/text() = 'FEMALE'" > 
      <Title> 
       <xsl:value-of select="../../../Name/title/text()" /> 
      </Title> 
      <Gender> 
       <xsl:value-of select="../../../Name/Gender/text()" /> 
      </Gender> 
      </xsl:if> 
     </xsl:for-each> 
     </Mother> 
    </PartnerParents > 
    </xsl:for-each> 
</Test> 

... aşağıda XML uygulanır:

<Test> 
    <Person> 
    <PersonType>PartnerParentsFarther</PersonType> 
    <Name> 
     <title>MR</title> 
     <Gender>MALE</Gender> 
    </Name> 
    <Address/> 
    <PersonKey> 
     <Key>a1093c4a-7c53-4de5-ad30-cb4140aec58</Key> 
     <ParentKey/> 
    </PersonKey> 
</Person> 
<Person> 
    <PersonType>PartnerParentsMother</PersonType> 
    <Name> 
    <title>MRS</title> 
    <Gender>FEMALE</Gender> 
    </Name> 
    <Address/> 
    <PersonKey> 
     <Key>a1093c4a-7c53-4de5-ad30-cb4140aec58</Key> 
     <ParentKey/> 
    </PersonKey> 
</Person> 
<Person> 
    <PersonType>PartnerParentsFarther</PersonType> 
    <Name> 
    <title>MR</title> 
    <Gender>MALE</Gender> 
    </Name> 
    <Address/> 
    <PersonKey> 
    <Key>a1093c4a-7c53-4de5-ad30-cb4140aec59</Key> 
    <ParentKey/> 
</PersonKey> 
</Person> 
<Person> 
    <PersonType>PartnerParentsMother</PersonType> 
    <Name> 
    <title>MRS</title> 
    <Gender>FEMALE</Gender> 
    </Name> 
    <Address/> 
    <PersonKey> 
    <Key>a1093c4a-7c53-4de5-ad30-cb4140aec59</Key> 
    <ParentKey/> 
    </PersonKey> 
</Person> 
</Test> 

... istenilen sonucu üretilen:

<Test> 
<PartnerParents> 
    <Father> 
    <Title>MR</Title> 
    <Gender>MALE</Gender> 
    </Father> 
    <Mother> 
    <Title>MRS</Title> 
    <Gender>FEMALE</Gender> 
    </Mother> 
</PartnerParents> 
<PartnerParents> 
    <Father> 
    <Title>MR</Title> 
    <Gender>MALE</Gender> 
    </Father> 
    <Mother> 
    <Title>MRS</Title> 
    <Gender>FEMALE</Gender> 
    </Mother> 
</PartnerParents> 
</Test>